本帖最后由 lazygc520 于 2013-06-07 09:37:32 编辑
$row2[0],'count'=>$row2[1]); } print_r$var); }// echo $a[$k]['5'].'
';?>
得到的结果：
Array [0] => Array [lotno] => 3207 [count] => 15 ))Array [0] => Array [lotno] => 3207 [count] => 15 ))Array [0] => Array [lotno] => 3206 [count] => 12 ) [1] => Array [lotno] => 3207 [count] => 3 ))Array [0] => Array [lotno] => 3207 [count] => 15 ))Array [0] => Array [lotno] => 3207 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))Array [0] => Array [lotno] => 3218 [count] => 15 ))
如何将这些二维数组合并到一个数组中并按lotno排序？
若lotno相同时，将对应count的值相加。请问下如何处理？
回复讨论解决方案)
$sql = "select DISTINCT b.packageno,a.stock_no from `stock_detail` as a,`kw_manage` as b where a.stock_no = '".$stockno."' and a.cust_no = replace b.cust_no, ' ', '' )";$result = mysql_query$sql);$res = array); //设置一个用于存放结果的数组while$row = mysql_fetch_array$result,MYSQL_ASSOC)){ $sql2 = "select lotno,countlotno) from `vp_barcode_2d_y` where packageno = '".$row['packageno']."' group by lotno order by lotno asc"; $result2 = mysql_query$sql2); $var = array); while$row2 = mysql_fetch_array$result2,MYSQL_NUM)) { ifisset$res[$row2[0]])) $res[$row2[0]]['count'] += $row2[1]; else $res[$row2[0]] = array'lotno'=>$row2[0],'count'=>$row2[1]); }}ksort$res); //因键名已处理成 lotno 的值，所以按键名排序就是按 lotno 排序